Wrong output, this is not working as soon as i encounter x, it is only pronting values before first x

#1
#2

hello @pranaynigam

dry run this part
ss

this will assign null to all the entries from index i onwards

#3

how to correct it, can you please edit my code?

#4 
	while (a[j] != '\0'){
		j++;
		
	}
	a[j+1]='\0';
	a[j]='x';
	
	
	for ( int k=i;k<=j;k++){
		a[k]=a[k+1];
	}

this is also giving segmentation fault . why?

#5

Consider a case where all elements are x your code wwill stuck in infinite cycle

#6

then how should i write the code? please edit my program.

#7

first move all x that are in right to the end and then move current x to the end or before x.
check this-

#8
#9

this code is giving segmentation fault

#10

This won’t work s[0] , this will always means first index of a, and it won’t get updated too. Try to implement like this

#11

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