With ios::sync_with_stdio(0);cin.tie(0);
#include<bits/stdc++.h>
using namespace std;
int main(){
ios::sync_with_stdio(0);cin.tie(0);
cout << “1st step” << “\n”;
int tc;
cin >> tc;
while(tc–){
cout << “hello” << “\n”;
}
}
Output:
1
1st step
hello
Without ios::sync_with_stdio(0);cin.tie(0);
Output:
1st step
1
hello
Why is the order of output different in both cases?
Hi Ravi ,
when you use ios::sync_with_stdio(0);cin.tie(0);…
then it will firstly take all input and print all the output at last of program.
Here
1 //input
1st step //output
hello //ouput
where as you dont use it , program will work normally by going line by line
As
1st step
1
hello.
hit like if u get it 
and mark it resolved.
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