Why is the address of the array coming out to be the same?

#1

Here is the code. I think it is similar to initializing like another variable, but I can’t justify myself why the address is the same always. It is like the for loop like
for(int i=0;i<n;i++) where i got initialized only one time? Another code (int var)
Thanks.

#2

When same variable is initialized again and again within a loop, its address in the memory remains same. So the same address is reused again and again. Only the content at that address may change.

1 Like
#3

@pratyush63 thanks, maybe it is because that compiler looks up for the variable and if it is already defined earlier, it allocates the same address or reuses it.

#4

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