Why im having error in this code is there any problem

#1

public class LoweUpper {

public static void check(String ch)
{
 
    if(ch >='A' && ch <= 'Z')
    {
        System.out.println("\n" + ch +
                " is an UpperCase character");
    }
 
    elseif (ch >= 'a' && ch <= 'z')
    {
        System.out.println("\n" + ch +
                " is an LowerCase character" );
    }
 
    else {
        System.out.println("\n" + ch +
                " is not an aplhabetic character" );
    }
}


public static void main(String []args)
{
   Scanner s=new Scanner(System.in);
   String str=s.nextLine();
   check(str);
   
 
}

}

#2

hey @missroy the problem in this code is that in the function ch is a String but ing if condition you are comparing a String(Ch) with a Character that’s why it is giving a error

#3

ok but we can declare String as charecter too?

#4

hey @missroy No you cannot declare String as Character.
but you can convert a String to character using String.valueOf(Ch);

#5

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#6

im trying to compare charecter this is my code and it is giving an error

#7

public class LoweUpper { public static void check(char[] ch) { if (ch >= ‘a’ && ch <= ‘z’) { System.out.println(“lowercase” ); } if(ch >=‘A’ && ch <= ‘Z’) { System.out.println(“UPPERCASE”); } else { System.out.println(“INVALID” ); } } public static void main(String []args) { Scanner s=new Scanner(System.in); int n=s.nextInt(); char ch[]=new char[n]; for(int i=0;i<n;i++) { ch[i]=s.next().charAt(0); } check(ch); } }