Why can't bernauli's trial be used for 2 consecutive heads question

#1

if we use bernauli’s trial for 2 consecutive heads question then the probability of getting HH is 1/4 hence the number of trials required is 4. HH will be considered as sucess and TT TH HT will be considered as failures

#2

Hi @yash_jjw

Could you please provide the reference for which you are asking this question as in the question link?
Or is it a general doubt because you have mentioned the heading as why can’t this be used?