WHY AM I GETTING ERROR: invalid type argument of unary '*' (have 'char')

#1

#include
#include
#include
using namespace std;
void frequency(string s)
{
pair<char,int>f[1000];

int i=0;
for(; i<1000 ; i++)
{
f[i]=make_pair(’\0’,0);
}
i=0;
f[0].first=*s.begin();
f[0].second=0;

for(auto c : s)
{
 if(*c==f[i])
 {
	 f[i].second++;
 }
 else
 {
	 i++;
	 f[i].first=*c;
	 f[i].second++;
 }
}
pair<int , int >p;
p.first=0;

for(int j=0 ; j<i+1 ; j++)
{
if(p.first<f[j].second)
p.second=j;
}
cout<<f[p.second].first;

}//end

int main()
{
string s;
getline(cin,s);

sort(s.begin(), s.end());

cout << s;

frequency(s);
return 0;
}

//ERRORS: source.cpp: In function ‘void frequency(std::string)’:
source.cpp:21:7: error: invalid type argument of unary ‘*’ (have ‘char’)
21 | if(c==f[i])
| ^
source.cpp:28:16: error: invalid type argument of unary '’ (have ‘char’)
28 | f[i].first=*c;
| ^

#2

@amangupta
c is of the type char here. So *c is not correct thing to use.
auto just assign the datatype which is needed, so here it is ‘char’.

Also if you have some more in doubt in then please provide the ide link of code.
Otherwise if now clear then please mark this doubt as resolved.

#3

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