When I am changing from binary to decimal if i give input like 001110 ,,, I am getting output as 40. What to do in this case?

#1

public class AnybaseToDecimal {

public static void main(String[] args) {
	
	System.out.println(anybasetoDecimal(001110,2));
	

}


public static int anybasetoDecimal(int snum , int sb) {
	int ans = 0;
	int mul = 1;
	while(snum>0) {
		int rem = snum%10;
		ans = ans + rem*mul;
		mul = mul*sb;
		snum/=10;
	}
	return ans;
}

}

#2

@LakshmiPrasanna0303,
https://ide.codingblocks.com/s/251057 corrected code

Don’t use int for input. Because 001110 is not an integer. You can use a string. Or if you want to use an integer don’t put any zeros before the number.

I have attached the string implementation in the code.

Your logic was correct

1 Like
#3

Please explain me this line in which you have written–
int rem = (snum.charAt(snum.length() - i - 1) - 48) % 10;

#4

@LakshmiPrasanna0303,
Say if the snum string is 001110. In order to convert from binary to decimal we need to start from the last char. So that will be “snum.charAt(snum.length() - i - 1)”.

So we get the character which is snum.charAt(snum.length() - i - 1). Now we need to convert this to int. So we subtract 48 from it which is the ascii value of ‘0’

#5

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