log 2^k=log n
it sould be?
but it is shown
log 2^k=n
how?
When he is taking log on both side step is not clear
hello @gaurav_kumar
In binary search size of array get half on each iteration
so we can represent size after each iteartion as
after iteration 0 -> N
after iteration 1 -> N/2
after iteration 2 -> N/2^ 2
after iteration 3 -> N/2^ 3
after iteration 4 -> N/2^ 4
after iteration 5 -> N/2^ 5
.
.
after iteration k -> N/2^ k
now we want to know after how many iterations our array size will become 1.
let say it is 1 after k iterations.
then using above formula we can write N/2^k=1
N=2^k
k=log2(N)
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