#include<bits/stdc++.h>
using namespace std;
void pi(int n,int i=0){
char a[10000];
cin>>a;
for(int k=1;k<=n;k++){
if(a[i]=='\0' || a[i+1]=='\0'){
return;
}
if(a[i]=='p' && a[i+1]=='i'){
int j=i+2;
while(j!='\0'){
j++;
}
while(j>=i+2){
a[j+2]=a[j];
j--;
}
a[i]='3';
a[i+1]='.';
a[i+2]='1';
a[i+3]='4';
pi(n,i+4);
}
else{
pi(n,i+1);
}
}
cout<<a<<endl;
}
int main() {
int n;
cin>>n;
pi(n);
return 0;
}
you code is not correct
n is no testcases means no of inputs given to you and corresponding to each input you have to print output
if n =3 then you have to take 3 inputs and print 3 output
but you are taking input only once that is first mistake
Correct way to doing
#include<iostream>
using namespace std;
void solve(char ch[], int i, char out[], int j) {
if (ch[i] == '\0') {
cout << out << endl;
return;
}
if (ch[i] == 'p' && ch[i+1] == 'i') {
out[j] = '3';
out[j + 1] = '.';
out[j + 2] = '1';
out[j + 3] = '4';
solve(ch, i + 2, out, j + 4);
} else {
out[j] = ch[i];
solve(ch, i + 1, out, j + 1);
}
}
int main() {
int t;
cin >> t;
while (t--) {
// take input
char ch[10000], out[10000];
cin >> ch;
// print output corresponding to given input
solve(ch, 0, out, 0);
}
return 0;
}
is your doubt resolved ??
or you need more assistance