What if when N is odd and it's (m^2-n^2) then how to solve this?

#1

You said that m^2-n^2 can be even or odd but how to find triplet when it’s odd and the part of m^2-n^2

#2

@cyberaj123
hello anand,
m^2-n^2 = > (m-n) * (m+n)=N

(m-n) * (m + n) = 1 * N
assign
m-n=1
m+n=N
and solve it