Unable to understand this logic

#1

why false is return why not true. Please give illustration with eg

#2

lets take the example given in video
apple bat batman

case 1 :
a.size() <= b.size() && b.substr( 0 , a.size()) == a return false

a = bat b = batman
clearly a is substring of b
so we need that batman comes first had we returned true then a would come before b
but we need b to be before a
so false is returned

b.size() <= a.size() and a.substr(0,b.size() ) == b return true

eg
a = batman and b = bat
b is substring of b ||
a need be to before b
hence true is returned

in case of anyother comparision
lexographic sort needs to be done
hence apple comes before any other element starting with b

#3

But if i tried in many cases true is also working in each cases

#4

when u pass true does it work

it would not be returning the desired results
like it would work
but not give correct answer

#5

on same order it was coming as it required to come
i tried
apple bat batman
output : apple batman bat
code also successfully accepted

#6

great if it got accepted bhaiya discussed the general way to approach this kind of sorting