Unable to understand the question

#1

the question is unclear to me
please explain with some other test cases

#2

hi @harshkasana17
N is the no. of cards in A(0)th stack.
Q is the no. of iterations you have to perform.
The third input is N numbers, representing the number of cards present in A(0)th stack.

Consider the following input:
INPUT:
N=5
Q=2
A(0)th stack : 1 2 3 4 5

Processing:
iterate for i =1 to Q;

for i=1(frst iteration):

Pop top element of A(i-1)th (A(0)th) stack i.e. 5
Check, ((top_element i.e. 5)%(ith prime number i.e. 1st prime number, 2)) == 0 ? Push top_element to B(i) i.e. B(1)th stack : Push top_element to A(i)i.e.A(1)th stack;
After repeating the same for all elements of stack A(0):
A(0)=[] i.e. empty as all elements have been popped.
A(1)=[5,3,1] as they are not divisible by 2.
B(1)=[4,2] as they are divisible by 2.

for i=2=Q (second and last iteration):

Pop top element of A(i-1)th (A(1)th) stack i.e. 1
Check, ((top_element i.e. 1)%(ith prime number i.e. 2nd prime number, 3)) == 0 ? Push top_element to B(i) i.e. B(2)th stack : Push top_element to A(i)i.e.A(2)th stack;
After repeating the same for all elements of stack A(1):
A(1)=[] i.e. empty as all elements have been popped.
A(2)=[1,5] as they are not divisible by 3.
B(2)=[3] as they are divisible by 3.

Output:
print elements of B(1),B(2),A(2)

2
4
3
5
1

Note: top element of the stack is popped first.