Unable to solve

#1

what is the base case? what is the logic here?

#2

hello @amit0001

base case should be ->
if n==1 then return 2 ( 0 or 1 both )

if n==2 then return 3 (00,01,10 these three)

and for n>2
u can use recurrence relation .

#4

okay
…

#5

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#6

Why are we returning 1 if n==0? If string length is 0, then there should be no binary string at all, isn;t it?

#7

…

it is done to make implementation easy.
if u have issue then refer above base cases