Unable to clr all testcases

#1
#2

if u want to do using stl then make 2 lists… one for odd and other for even… then print ans accordingly…

#3

I have cleared 2 testcases using this approach, i am unable to understand why other 2 are not cleared

#4

are bhai khud dry run krke dekho order aage piche hoga aise… 2 list use kro… agr hm linked list implement bhi krte hai to even and odd dono ke liye alg head pointers maintain krte hai and in end join krte hai…
5
1 2 4 7 6
ye input pe dekhlo ur code is failing… 2 min lgenge paper pe dry run krne ke liye…
and ye jruri thodi hai ki partial test case chlge to tumhare code ka logic shi hai…

#5

For input, 5- 1 2 4 7 6 the output is 7 1 2 4 6 which i believe is correct, all evens are after odds, should the output be 1 7 2 4 6?

#6

ok… just a min… i understood the ques the vice versa… i thought odd after even… let me see ur code

#7

consider this input…
5
1 2 3 4 5

ur o/p 5 3 1 2 4
expected o/p 1 3 5 2 4

ur soln is basically changing the order of odd elements… just bcoz u are pushing in front whenever u encounter new odd element… are u getting my point

#8

yes, got it, let me try another approach

#9

yes… just use 2 list… one for storing odd elements and other for even elements

#10

done, thanks for ur help.

#11

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