Ultra-fast-mathematicians

#1

please review the code

#2

hey @bhavuk_tomar

#include <iostream>
using namespace std;
int main() {
    string s1,s2="";
	string s3;
    int i,j,t;
    cin>>t;
    //for(int k=1;k<=t;k++)
	while(t--)
    {
	s3="";//added this here so that for each testcase we start with empty s3
    cin>>s1>>s2;
    for(i=0;i<s1.length();i++)
    {
        if(s1[i]==s2[i])
        s3.append("0");
        else 
        s3.append("1");
    }
    cout<<s3<<endl;
    }
    return 0;
}
#3

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