please elaborate how :
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int j = sizeof (a) / sizeof (int) - 1 works to give the last element.
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at the end we did i++ and j-- but we had done that in if conditions so why did we do it again
please elaborate how :
int j = sizeof (a) / sizeof (int) - 1 works to give the last element.
at the end we did i++ and j-- but we had done that in if conditions so why did we do it again
Hey @bhavaysinghal
This gives size of array in bytes = 4*no of elements
Now sizeof(int)=4bytes
Then int j=4*n/4-1==n-1
If sum ==target then we print the pair and then we should move i and j right
Because if we dont then sum==target always and will be stuck in an infinite loop