TRIPLET - Linked List

My code is passing only for 2 out of 6 test cases. It gives wrong answer for the rest o the 4.
The problem statement is:
Given three linked lists, say a, b and c, find one node from each list such that the sum of the values of the nodes is equal to a given number say, Target. As any number of answers can be possible return the first one you get while traversing.
Here is my code:

public static void main(String[] args) throws Exception {
Scanner scn = new Scanner(System.in);
int x = scn.nextInt();
int y = scn.nextInt();
int z = scn.nextInt();
LinkedList l1 = new LinkedList();
LinkedList l2 = new LinkedList();
LinkedList l3 = new LinkedList();
for (int i = 1; i <= x; i++) {
l1.addLast(scn.nextInt());

	}
	for (int i = 1; i <= y; i++) {
		l2.addLast(scn.nextInt());

	}
	for (int i = 1; i <= z; i++) {
		l3.addLast(scn.nextInt());

	}
	int target = scn.nextInt();
	sum(l1, l2, l3, target);
}

public static void sum(LinkedList l1, LinkedList l2, LinkedList l3, int target) {
	for (Node p1 = l1.head; p1 != null; p1 = p1.next) {
		for (Node p2 = l2.head; p2 != null; p2 = p2.next) {
			for (Node p3 = l3.head; p3 != null; p3 = p3.next) {
				if(p1.data+p2.data+p3.data==target) {
					System.out.println(p1.data+" "+p2.data+" "+p3.data);
				}
			}
		}
	}
}

Hi Aditya,
After printing the answer you have to use a break or return statement because consider a case where more than 1 triplet exist then your program will print all the triplets but acc. to question you have to only print 1 triplet you find first.

Thank you so much , it worked !!

Hi Adtiya
I am marking your doubt as resolved. Feel free to reopen the thread if you face any more issues.