Time complexity

#1

Find the time complexity of the given code.

int count = 0;
for (int i = N; i > 0; i /= 2)
for (int j = 0; j < i; j++)
count++;

What is the time comp of this code and how??

#2

Hey
The time complexity is O(n).
For a input integer n, the innermost statement of fun() is executed following times.
n + n/2 + n/4 + … 1
So time complexity T(n) can be written as
T(n) = O(n + n/2 + n/4 + … 1) = O(n)
The value of count is also n + n/2 + n/4 + … + 1

#3

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