The code breaks

#1

what is my mistake in this code ?
n=int(input())
for i in range(1,11):
j=2
while j<n:
if n%j==0:
print(‘Not prime’)
else:
print(‘Prime’)
j+=1

#2

Hello Anurag, can you pls tell me what are you trying to do exactly. And why are you running the loop from 1 to 11. Exactly what is your motive in this ques. Pls let me know I will help you out for sure. It is not clear to me exactly what are you asking.
Thanks :slight_smile:
Happy Coding !!

#3

1 to 11 bcz I think it will run the core to 1-10 both inclusive…that’s why … And its just prime and not prime code

#4

Hello Anurag, yes you are right the loop will run from 1 to 10 inclusive. But by this you are trying to know whether the ith no. is prime or not and if this is so. You can use break in this like this.

for n in range(1,11):
	i = 2
	val = True
	if n < 2:
		val = False
	else:	
		while i*i <= n:
			if n%i == 0:
				val = False
				break
			i+=1	

	if val:
		print("Prime")
	else:
		print("Not Prime")

And if you really want to find the no. n whether it is prime or not then you can check it like this.

n = int(input())

i = 2
val = True
if n < 2:
	val = False
else:	
	while i*i <= n:
		if n%i == 0:
			val = False
			break
		i+=1	

if val:
	print("Prime")
else:
	print("Not Prime")

Pls check this and let me know if it is clear to you and let me know.
Thanks :slight_smile:
Happy Coding !!

#5

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