Test question 10

#1

Given the following code snippet :

string s = “bca”;

do {
cout << s << ’ ';
} while(next_permutation(s.begin(), s.end()));

cout << s;
What is the output of the given code?

please explain the answer

#2

Hi @sushreesamapika1512
Output for this code snippet will be :
bca cab cba abc

In here next_permutation is used to rearrange the elements in the range [first, last) into the next lexicographically greater permutation. A permutation is each one of the N! possible arrangements the elements can take (where N is the number of elements in the range). Different permutations can be ordered according to how they compare lexicographically to each other. And also the function, next_permutation(a.begin(), a.end()) returns ‘true’ if the function could rearrange the object as a lexicographically greater permutation. Otherwise, the function returns ‘false’. So as you can see we get cba as second last string because there is no lexicographically greater permutation possible for cba.

#3

heyy but last is abc.this is incoreect