Test Case Failing

#1

test case 0 is failing

import java.util.*;
public class Main {
public static void main(String args[]) {
// Your Code Here
Scanner scn = new Scanner(System.in);
int n = scn.nextInt();
int [] arr = new int[n];
for(int i = 0; i < arr.length; i++){
arr[i] = scn.nextInt();
}

    System.out.println(isSorted(arr, 0));
}
public static Boolean isSorted(int[] arr, int i){
    Boolean ans = true;

    if(i >= arr.length-1){
        return true;
    }
	if(arr.length==1){
        return true;
    }

    if(arr[i] > arr[i+1]){
        ans= false;
    }else{
        isSorted(arr, i+1);
    }
    return ans;

}

}

#2

HI @shruti_codess28
Here we have to Recursively traverse over the array. If it any point we reach an index where arr[i] > arr[i + 1] , we return false. If not , we simply return the result we obtain from further recursive call. Base case would be if we reach the end of the array while traversing , where we return true.

I have shared updated code here please check:-

#3

okay thanks… but what was wrong with my code why test case 0 was failling??

#4

okay thanks… but what was wrong with my code why test case 0 was failling??

#5

Because of your base case i have explained that in explanation above code.

#6

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