Take as input N, the size of an integer array. Take one more input, which is a list of N integers separated by a space, and store that in an array. Write a recursive function which prints true if the array is sorted, and false otherwise

how to solve this sorted array question

@tanishka972,
You need to take an input of n numbers and store it in an array. After that you need to pass the array to a function and check if the array is sorted or not, using recursion.
Return false if the array is not sorted.

public class hcf_gcd{
public static void main(String args[])
{

	Scanner in=new Scanner(System.in);
	int scn=in.nextInt();
	int a[]=new int[scn];
	
	
}
public static boolean rec(int[] a)
{
	int i;
    for(i = 0; i < a.length; i++)
    {
        if (a[i] < a[i+1])
        {
            return true;
        } 
        else {
            return false;   
        }
    }
}

}

IS IT LIKETHIS?

@tanishka972,

int[] arr=new int[N];
	for(int i=0;i<str.length;i++)
	{
		arr[i]=in.nextInt();
	}
	System.out.print(isSorted(arr,0));
}

static boolean isSorted(int[] arr,int si)
{
    if(si>=arr.length-1)
    return true;
    boolean res= (arr[si+1]>=arr[si]) && isSorted(arr,si+1);
    return res;   
}

@tanishka972,
Please watch the videos if you haven’t for reference

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public class Main {
public static boolean isSorted(int[] arr,int i){
if(i==arr.length-1){
return true;
}
if(arr[i]>arr[i+1]){
return false;
}else{
boolean ans=isSorted(arr,i+1);
return ans;
}
}
public static void main(String args[]) {
Scanner scan=new Scanner(System.in);
int N=scan.nextInt();
int[] a=new int[N];
for(int j=0;j<N;j++){
a[j]=scan.nextInt();
}
System.out.println(isSorted(a,0));
}
}

This code is giving me NoSuchElementException again and again. Could u tell where i m wrong??