Sum of two Arrays Testcase 3

#1

I cant get through all the testcases please help me correcting my code:-

#include
using namespace std;
int arrtonum(int a[],int s){
int ino = 1,num=0;
for(int i=0;i<s;i++){
num= (num * 10) + a[i];
}
return num;
}
int main() {
int n,m;
cin>>m;
int a[m]={0};
for(int i=0;i<m;i++){
cin>>a[i];
}
cin>>n;
int b[n]={0};
for(int i=0;i<n;i++){
cin>>b[i];
}
int rem=0,reverse=0;
int sum= arrtonum(a,m) + arrtonum(b,n), ar[max(m,n)]={0};
int j=max(m,n)-1;
while(sum!=0){
rem=sum%10;

 ar[j]=rem;
 j--;
 reverse=reverse*10+rem;     
 sum/=10;    
} 
for(int i=0;i<max(m,n);i++){
     cout<<ar[i]<<", ";
}  
cout<<"END"<<endl;
return 0;

}

#2

hi @sy7176442_ca8a8991a7ddc322
refer this code -->

#include<iostream>
using namespace std;
int main()
{
	int n1,n2;
	cin>>n1;
	int arr1[n1];
	for(int i=0;i<n1;i++)
	{
		cin>>arr1[i];
	}
	cin>>n2;
	int arr2[n2];
	for(int i=0;i<n2;i++)
	{
		cin>>arr2[i];
	}
	int m=max(n1,n2);
	int arr3[m];
	int carry=0;
	int i=n1-1;
	int j=n2-1;
	int k=m-1;
    
	while(k>=0)
    {  int sum=carry;
       if(i>=0){
           sum+=arr1[i];
       }
       if(j>=0){
           sum+=arr2[j];
       }	
       
       int r=sum%10;
       int q=sum/10;
       arr3[k]=r;
       carry=q;
       i--;
       j--;
       k--;
    }
    if(carry!=0)
    cout<<carry<<", ";
    for(int i=0;i<m;i++)
    {
    	cout<<arr3[i]<<", ";
    }
    cout<<"END"<<endl;
    return 0;
}
#3

hi @sy7176442_ca8a8991a7ddc322
i hope its clear now??

#4

I hope I’ve cleared your doubt. I ask you to please rate your experience here
Your feedback is very important. It helps us improve our platform and hence provide you
the learning experience you deserve.

On the off chance, you still have some questions or not find the answers satisfactory, you may reopen
the doubt.