Sum of even placed digits and odd placed digits

#1

It will be done using for loop and if else or any other method

#2

hi @kumarakash121005
u will have to use loops and if-else only to solve this problem…
refer this -->

#include <iostream>
using namespace std;
int main() {
    int n;
    cin>>n;

    int pos = 1;
    int odd_sum = 0;
    int even_sum = 0;

    while(n > 0){
        int x = n%10;
        n = n/10;
        if(pos%2 == 1){
            odd_sum += x;
        }
        else{
            even_sum += x;
        }
        pos++;
    }
    cout<<odd_sum<<endl;
    cout<<even_sum<<endl;
}
#3

hi @kumarakash121005
is it clear or u still face any difficulty???

#4

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