Strings-Remove Duplicates

#1

import java.util.*;
public class Main{
public static String remove(String str,char last_rem){
if (str.length() == 0 || str.length() == 1)
return str;
if (str.charAt(0) == str.charAt(1))
{
last_rem=str.charAt(0);
if(str.length()>1 && str.charAt(0) == str.charAt(1))
str=str.substring(1,str.length());
str=str.substring(1,str.length());
return remove(str,last_rem);}
String rem_str=remove(str.substring(1,str.length()),last_rem);
if (rem_str.length() != 0 && rem_str.charAt(0) == str.charAt(0)) {
last_rem=str.charAt(0);
return rem_str.substring(1,rem_str.length());}

if (rem_str.length() == 0 && last_rem == str.charAt(0))
return rem_str;
return (str.charAt(0) + rem_str);
}

  static String removeA(String str)   
  { 
         char last_removed = '\0'; 
         return remove(str, last_removed); }

public static void main(String args[]){
try{
Scanner sc=new Scanner(System.in);
String str=sc.nextLine();
String res=removeA(str);
System.out.println(res);
}
catch(Exception e){System.out.println(e);}}
}

#2

Hi @Sweta,
Your code is majorly wrong . It does not work even for basic cases … For example it won’t run for testcase ‘aaaaaaaa’ . Please correct the code according to this testcase and i hope then it will pass all the test cases . However i would also suggest to use iterative approach as this question is quite basic and using recursion only makes it harder to think.

#3

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