String tokenizer 1

#1

ptr=strtok()
here ptr stores address of string
and then by just cout<<ptr why the address of the string is not printed ??? and how come the strings are printed.

#2

Hello @sharmalakshyarocks,

The << operator on std::cout is overloaded. Its behaviour depends on the type of the right operand. (It’s actually several different functions, all named operator<<; the compiler decides which one to call.)

  1. If you give it a char* or const char*, it treats the operand as a pointer to (the first character of) a C-style string, and prints the contents of that string:
    \

const char * ptr = “hello”;
cout <<ptr; // prints “hello”

  1. If you give it a char value, it prints that value as a character:
    \

cout << *ptr; // prints “h”
cout << ptr[0]; // the same

  1. If you give it a pointer of type void*, it prints that pointer value (in some implementation-defined way, typically hexadecimal):
    \

cout << static_cast<const void*>(ptr); // prints something like 0x4008e4

Hope, this would help.
Give a like, if you are satisfied.