if we have to store -8 in 4 bist, how will we store?
in this video, i could not get as for 8, it is taking as 1000, which i think is wrong as in 4 bits,1 bit is for sign.
Also tell in case of 4 bits, range is from -8 to 7…i understood 7, but why -8?
hello @sp_wizard
yeah for 4 bit signed number we cannot store 8 in it.
becuase computer store negative numbers in 2’s compliment form , which has only one 0.
range of n bit signed number-> - 2^(n-1) …2^(n-1)-1
yeah for 4 bit signed number we cannot store 8 in it…but in a 4 bit signed number,1 bit is for sign, so how can we store 8?
we cannot( we will need more than 4 bit to store it) , if u try then u will get negative output becuase of range overflow.
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