Sorted function using Lambda Functions

#1

In the tutorial, it was mentioned that we can sort a tuple from the x [ 1 ] index as well by using Lambda function.We assign the value “key=lambda x:x[1]” but when I use some other variable other than "key " then the sorted function doesn’t work

#2

‘key’ is the parameter of sorted function. You cannot have any other name for that. Let’s say you have a list:
L = [(1,2), (3,1), (4,-1)]
To sort this list based on second element of tuple. You can either do:
sorted(L, key=lambda el: el[1])
Here el represents each element of the list, which is a tuple. You can use any identifier/ name instead of el, like x, y, z but cannot change the name of the actual parameter of sorted fn which is ‘key’

If you don not want to use lambda expression you can instead create a fn:
def func(x):
return x[1]
Know that here x is the tuple, the element of our list.
Then use sorted fn:
sorted(L, key=func)

#3

HI @rishavraj1808_a240d978fe1ee795 hope your doubt has been resolved… for now I closing this doubt if you still have any isuue please do contact

#4

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