In the following lines of code:
int *p=new int(30);
cout<<*p;
int *arr=new int[30];
cout<<arr[0]<<endl;
Why didn’t we put * before arr[0] just like we did for the variable p?
Please help…
Some doubts in dynamic Memory allocation
@Tiwary725 It is because *p and *arr both are pointers.
When we use *p it means that we want to use the value present at address which is pointed by pointer p.
Whereas we use arr[0] because arr contains the base address of the integer array and we go to the 0th location using arr[0] and find the value .
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