Smart keyboard easy

#1

#include
#include
using namespace std;

char keypad[][10] = { " ", “.+@$”, “abc”, “def”, “ghi”, “jkl” , “mno”, “pqrs” , “tuv”, “wxyz” };

void print(char* in , char* out, int i, int j)

{

/// base case
if(in[i]==’\0’)
{
out[j]==’\0’;
cout<<out<<endl;
return;
}

 /// rec case
 int digit=in[i]-'0';
// if( digit==0)
 //{
  //   print(in,out,i+1,j);
 //}

 for(int k=0;keypad[digit][k]!='\0';k++)
 {
     out[j]= keypad[digit][k];
     print(in ,out, i+1, j+1);
 }

}

int main()
{
char in[11];
char out[11]={0};
cin>>in;
print(in,out,0,0);
return 0;

}

i cant understand how this code works . explain please
the how recursion is working here

#2

Save your code on ide.codingblocks.com and then share its link.

#4
#5

The recursive relation for phone keypad question has been discussed in the lecture video. You can refer that first. Also line 17-20 is not required here because when you get a 0, you do not have to skip but introduce a white space.

#6

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