Size of pointer a

#1

int *a= new int[n]
cout<<sizeof(a)

why it is giving 8 as in video sir told thayt it gives the size of pointer a which in this is integer so it should be 4.

#2

Hello @tejuschaturvedi0
int *a=new int[n]
cout<<sizeof(a);

this will give you 8 because you are printing size of a pointer
you will get 4 if you print size of integer variable
int a=10;
cout<<sizeof(a); // this will give 4

int a=4;
int *b=&a;
cout<<sizeof(b);// this will also give 8 as it is pointer

char var=‘a’;
char *ptr=&var;
cout<<sizeof(ptr)<<endl; // this will also give 8 as it is also pointer

#3

So why size of a pointer is 8 only. Does it changes with data type.

#4

@tejuschaturvedi0 The 8 -byte count taken up by pointers is crucially exclusive to 64-bit machines, and for a reason - 8 bytes is the largest possible address size available on that architecture. Since one byte is equal to eight bits, 64 bits / 8 = 8 represents the size of a pointer .

#5

and for 32 bit system the size of the pointer will come out to be 4 byte as 32/8=4 bytes.

#6

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