Single Element in a Sorted Array

#1

question–>


code–>

approach–>
using binary search (not xor method), if the starting position of the even then we have to search on the right side becuase the lonely element has not occurred else we search on the left side because the character has occured
gfg link–>

i am not able code the logic it gives tle

#2

Hey @sheikhhaji18
Do a dry run to understand the corrections if req

#3

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