Since 15 is not present so it should return the end iterator? the end iterator will be 6 or 7?{
sets;
s.insert(1);s.insert(5);s.insert(7); s.insert(2);s.insert(12);s.insert(10); // so the final set is 1,5,7,2,12,10??
auto it = s.lower_bound(15);
cout<< *it <<endl;
return 0;
}
Please explain the output for this.
