Segmented sieve index doubt

#1

Here as explained in the video
suppose the segmented sieve is from 99 to 144
so m=99 and n=144
index of segmented sieve must start from (m-m) i. e: =0

In the code
int start = (m/x)*x; // This equals to (99/2)*2 = 98

Now //in marking all multiples code

for(int i = start ; i <= n ; i+=x ){ //Here i = 98

segment [ i-m ] = 1 ; // Here ( i - m ) = ( 98 - 99 ) = -1

}

So there won’t be an indexing error in the code ???

#2

@hp_tony_21
yes ,you are right
for this you have put one condition
if(start<m)start+=x;/// next multiple of x