The code that is provided for the reverse of a no. fails when there are 0’s before or after first natural number.
for Eg;
if we input 1234567890
the output is 987654321
if we input 0012
the output is 21
so, my question is how can we solve this problem.one way might be to calculate the no. of digits in the number entered and run the loop for that many times but even the divison by 10 remained by 10 method fails to calculate the no. of digits.
so with the knowledge that we have and without using arrays or anything how can this issue be resolved.
Reverse of a No
if we are given 120 to reverse its output will be 21 only because starting 0’s have no significance…
if you want to print these 0’s then using an array is the best approach
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