Related to sum of digits

#1

why in some places there is n%10 and in others there is n/10
??

#2

hi @sethyamir5

#include <iostream>
using namespace std;
int main() {
    int n;
    cin>>n;
    int sum = 0;
    while(n > 0){
        int rem = n%10;
        sum += rem;
        n = n/10;
    }
    cout<<sum;
}

so what we are supposed to do is find the sum of all digits in the number…
when we do n%10, we are extracting individual digits… and in n/10, we are reducing the number by one shift…

consider an example say n = 12
when we do first %, we get rem = 2, and by n/10, we reduce it to n = 1…
now again when we do %, we get rem = 1, and on performing n/10, we get n = 0.1
so now n goes less than 0 and while loop breaks…
Hope it clears ur doubt…

#3

hi @sethyamir5
I hope its clear now??

#4

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