Recursion duplicate

#1

not all char are getting seprate by *
#include<bits/stdc++.h>
using namespace std;
void replaceduplicates(string arr,int i,int n){
if(n==0){
cout<<arr;
return;
}
if(arr[i]==’\0’)
{
cout<<arr;
return;
}
else if(arr[i]==arr[i+1])
{
// hell o o p \

	arr[n+1]='\0';
  for(int k=n-1;k>i;k--)
  {
  	arr[k+1]=arr[k];
  }
  arr[i+1]='*';
  replaceduplicates(arr,i+2,n+1);

}
else
{
replaceduplicates(arr,i+1,n);

}

}
int main() {
char arr[10000];
cin>>arr;
replaceduplicates(arr,0,strlen(arr));
return 0;
}

#2

please send the link of code

paste you code at

click on file->save->link will be generated
send the link of code generated
it will look like https://ide.codingblocks.com/s/258793

#3
#4
  1. use character array instead of string in function line no 3
  2. increase n also (line 21)
  3. at line no 16 correct statement
    for(int k=n;k>=i;k–)
    you forgot k>=i (equal to)

Modified Code

i hope this helps
if yes hit a like and don’t forgot to mark doubt as resolved :grinning:
if you have more doubts regarding this feel free to ask

1 Like
#5

why k==i? we have to shift all char btw n and i na not i and then after i place * so we should not include i na?

#6

okay
yes this will also work
for(int k=n;k>i;k–)

#7

i hope your doubt is resolved
so please mark it as resolved

#8

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#9

great explanation, thanks