Realted to basic c alculator

#1

it shows time limit exceeded
plz check.
int main() {
char ch;
cin>>ch;
while ((ch!=‘x’) || (ch!=‘X’) ){
if(ch==’+’){
int n1,n2;
cin>>n1>>n2;
cout<<n1+n2<<endl;

	 }
	 else if(ch=='-'){int n1,n2;
		 cin>>n1>>n2;
		 cout<<n1-n2<<endl;
		 

	 }
	 else if(ch=='*'){int n1,n2;
		 cin>>n1>>n2;
		 cout<<n1*n2<<endl;
		 
	 }
	 else if(ch=='/'){
		 int n1,n2;
		 cin>>n1>>n2;
		 cout<<n1/n2<<endl;
	 }
	 else if(ch=='%'){
		 int n1,n2;
		 cin>>n1>>n2;
		 cout<<n1%n2<<endl;
		 
		 
	 }
	 else{
		 cout<<"invalid response . try again"<<endl;

	 }
	 cin>>ch;
 }

return 0;

}

#2

use && here as we want the loop to break if EITHER of these conditions becomes false

#3

maam it still not working showing same error

#4

@avverma11057 please share your code by saving it on cb ide

#5

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