import java.util.*;
public class Main {
public static void main(String args[]) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
int ans=0,left=0,right=0;
int []a=new int[n];
for(int i=0;i<n;i++)
{
a[i]=sc.nextInt();
}
for(int i=0;i<n;i++){
for(j=n-1;j>=0;j–)
{
if(a[i]>left){
left=a[i];
}
if(a[j]>right){
right=a[j];
}
}
if(left>right){
ans=ans+left-a[i];
}
else
ans=ans+right-a[i];
}
System.out.print(ans);
}
}
plz coorect my code it is not compiling
@karthik1989photos,
you have not declared j. declare j as int j.
Also your approach is incorrect.
Suggested Approach:
An element of an array can store water if there are higher bars on left and right. We can find the amount of water to be stored in every element by finding the heights of bars on the left and right sides. The idea is to compute the amount of water that can be stored in every element of the array. For example, consider the array {3, 0, 0, 2, 0, 4}, we can store two units of water at indexes 1 and 2, and one unit of water at index 2.
Pre-compute highest bar on left and right of every bar in O(n) time. Then use these pre-computed values to find the amount of water in every array element.
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