A complete binary min-heap is made by including each integer in [1, 1023] exactly once. The depth of a node in the heap is the length of the path from the root of the heap to that node. Thus, the root is at depth 0. The maximum depth at which integer 9 can appear is _____________
how to solve this question …
please explain in easiest way and more deep …
hello @vishal_sangal_123
here node with integer 1 has to be at root only. Now for maximum depth of the tree the following arrangement can be taken. Take root as level 1.
make node 2 at level 2 as a child node of node 1.
make node 3 at level 3 as the child node of node 2.
and so on for nodes 4,5,6,7
make node 8 at level 8 as the child node of node 7.
make node 9 at level 9 as the child node of node 8.
Putting other nodes properly, this arrangement of the complete binary tree will follow the property of min heap.
So total levels are 9. node 9 is at level 9 and depth of node 9 is 8 from the root.
I hope I’ve cleared your doubt. I ask you to please rate your experience here
Your feedback is very important. It helps us improve our platform and hence provide you
the learning experience you deserve.
On the off chance, you still have some questions or not find the answers satisfactory, you may reopen
the doubt.