Question number 8

#1

What will be the answer to Q8? Can you please explain?

#2

hey @Mohit2000 ,
This is actually a bit simple.
When we are doing [ A() ]*count , then it makes copies of same class object multiple times,
So if you check printing it then you will see that , it shows same memory address.

hence , when we do , b[2].x = 5 , as it refers to same memory address , hence we get a stream of same values on printing it.

Now , how can we correct it.
To correct we just change this above creation of list from
b= [A()]*10
to
b = [A() for i in range(10)]

in this way we are creating different object ( means every object has different memory location ) every time we iterate to create it.

I hope this helped you :slightly_smiling_face:.

Thank You and Happy Learning :slightly_smiling_face:.

#3

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