Question broken?

#1

freq of characters in a string:

#include
#include

using namespace std;

void freq(string s){
int fre[26]={0};
char result;
int len=s.length();

for(int i=0;i<len;++i){
	fre[s[i]-'a']++;
}
for(int i=0;i<26;++i){
	if(fre[i]>0){
	result=(char)(i + 'a');
	cout<<result<<fre[i];
	}
}

}
int main() {
string s;
getline(cin,s);
freq(s);
return 0;
}

#2

hello @granthdhir
u have to compress only consecutive same character.

for example->
aaaabba will be compressed as
a4b2a1

#3

I solved the problem with the following code :

#4

https://ide.codingblocks.com/s/479656 ,is there a better approach to the problem?

#5

no, this is efficient.

#6

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