Query regarding dynamic array

#1

if i have a dynamic array arr ,
then arr[i] would represent the value at that index or it would be a pointer to the ith index of the array

#2

@Parmeet-Kalsi-1631789033630118 arr[i] gives value at that index. arr+i will give address of that index.

Please mark the doubt as resolved if I have cleared your doubt.

#3

Then in the video when our function is set to returning by reference then why we are using
return arr[i];
Not
return arr +i;

#4

Code is saved at 17901 by bhaiya
Function is
int& operator [](int i){
return arr[i];
}

So i am asking why not
return arr +i;

#5

@Parmeet-Kalsi-1631789033630118 arrays are sent by reference always.

#6

I am asking about the return type

#7

If the code would have been

int operator [](int i){
return arr[i];
}

Then this must have returned the value at the ith index of the array.

So i am asking here the code is

int& operator [](int i){
return arr[i];
}

and this is returning the address of ith index of the array as given in the video .
So i am asking if we are to return the address of ith index of array then in the above code it should be

return arr+i;
But why is it not so?

#8

@Parmeet-Kalsi-1631789033630118 that is not the purpose of it at all, and it has nothing to do with the array being dynamic or static.
If you return arr[i] just the value will be returned. So by adding &, we can return it by reference.

This is not the same as a function argument, dont get confused between them.

#9

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