Pythagorous triplet

#1

beside using abs() and I am getting positive values of X and Y
I have passed test case 0, 1 and 2
I am not able to pass test case 4 and test case 5

Please help me finding

#2

hello @jatinnirwan08
pls save ur code at cb ide and share it link with me

#3

#include
#include
using namespace std;
int main() {
long long int N;
cin>>N;
double p=0;
if(N==0||N==1||N==2)
{
cout<<-1;
}
else if(N%2==0)
{
p=N/2;
p=abs§;
cout<<(pp)-1<<" "<<(pp)+1<<endl;
}
else if(N%2!=0)
{
p=(N*N)/2;
p=abs§;
cout<<p<<" "<<p+1<<endl;
}
return 0;
}

#4

not here.

go to this link -> https://ide.codingblocks.com/

paste ur code in editor .
press ctrl + s and then save.

a url will be generated in search bar , copy that url and paste here in this thread

#5
#6

check now->

#7

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