Pushing index still test case 2 not passed

#1

int[] a = new int[prices.length];
stack.push(0);
a[0] = 1;
for (int i = 1; i < prices.length; i++) {
if (prices[i] < prices[stack.top()]) {
while (!stack.isEmpty()) {
stack.pop();
}
}
stack.push(i);
a[i] = stack.size();
}
return a;

}
#2

refer tot this:

public static int[] StockSpanUsingStacks(int[] prices, Stack<Integer> stack) throws Exception {

        // span array stores the value of stock span for each day
        int[] span = new int[prices.length];

         // pushing the index of first day
        stack.push(0);

        // span for 1st day will always be 1
        span[0] = 1;

        // Iterating over the prices array
        for (int i = 1; i < prices.length; i++) {

           // poping days from stack when price of the i th day is greater than the price of day which is on top of stack
            while (stack.size() != 0 && prices[i] > prices[stack.top()]) {
                stack.pop();
            }

            if (stack.size() == 0) {

             // then all the previous prices are smaller than the price on the  ith day 
                span[i] = i + 1;
            } else {

              // the previous highest price will be on the top of the stack 
                span[i] = i - stack.top();
            }

              // pushing the index of the price array which is the number of day in stack
            stack.push(i);
        }
        return span;

    }