Psedocode Assignment

#1

sir, i am not able to get the logic to print the pattern. what should be the logic to to write second for loop in the pattern

#2

Hello @chaman9,

If you are taking about the pattern:
1
2 3
4 5 6
7 8 9 10

When you have to print a pattern, always try to find the relationships:
Observations:

  1. first(1) line has 1 element
    second(2) has 2 elements
    third(3) line has 3 elements and so on…

  2. The values you have to print are continuous:
    1 2 3 4 5 6 7 8 9 10
    Take a variable and initialize it to 1 (before the loops)
    after printing it’s current value inside the second loop increment it.

APPROACH:

  1. temp=1;
  2. for i=1 to 4 do
    2.1. for j=1 to i do
    2.1.1. print temp;
    2.1.2. temp=temp+1;
    2.2. end loop
  3. end loop

Now, try to write pseudocode yourself.
Hope, this would help.
Give a like if you are satisfied.

#3

Hey virender actually i am asking for the pattern given in the assignment

#4

Hey @chaman9,

Can you share the pattern.

#5

hey virender, i was talking about this one
1
232
34543
4567654
567898765

#6

So @chaman9, in this case you can deduce the following observations:

  1. first(1) line starts with 1
    the second(2) line starts with 2
    and so on…

  2. each line contain 2*(line no.)-1 elements

  3. increment values the current line no. times
    and then decrement it (line no.-1) times

  4. There are two separate inner loops:
    one for increment purpose and another for decrement

Approach:
for(int i=1;i<=5;i++){
int j;
for(j=i;j<j+i;j++){
cout<<j<<" “;
}
for(j=j-1;j>=i;j--){
cout<<j<<” ";
}
cout<<endl;
}

Try to write a pseudocode

1 Like
#7

Thanks a lot bro i will write it.

#8

Anytime @chaman9,

Please mark it as resolved if you don’t have any doubt regarding this.

#9

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#10

Hi @chaman9
Is there still any doubt in how to approach the question,
please elaborate on your query

#11

Thank you for help virender, actually today only i opened coding blocks.
i was travelling back to hometown

1 Like
#12

Anytime @chaman9,

Mark it as resolved now.

#13

already marked it as solved.