Can you please help me out with this problem?
Problem 3 Maths quiz
@himanshugupta8 i would be able to help you in the better way if you could give the problem link here .
there is nothing in the link .
i think it is your portal question so you can share the screenshot .
hey @himanshugupta8 let’s consider we have 6 numbers and out of which take two numbers say a and b ,consider we need to have (a-b) as a multiple of 5 i.e (a-b)%5 =0 this implies (a%5-b%5)=0
i.e. a%5 =b%5 ; this means that out of 6 numbers we have to find the probablity that any two number has same value%5 ,possible values of anyvalue%5 is 0,1,2,3,4 and we have 6 numbers so according to pigeon hole principal we are bound to have two numbers with same value%5,
thus the answer should be 1.
if you have doubt in any point you can ask here .
and if your doubt is resolved please mark this doubt as resolved .
Happy Learning !!
Thanks… I got it.
But can you please tell that don’t we have to find the probability of number of pairs for which their difference is multiple of 5?
I misinterpret the question…But do you know how to find the probability of number of pairs for which their difference is multiple of 5?
if you feel that your doubt is cleared please mark this doubt as resolved .