Print all the numbers before the cumulative sum become negative

#1

i am not able to solve rhis probleml please tell me how to accept the integers .give me a hint for it

#2

check out this code

#include<iostream>
using namespace std;

int main() {

	int n;
	int sum = 0;
	cin >> n;
	while (true)
	{
		sum = sum + n;
		if (sum >= 0)
		{
			cout << n << endl;
		}

		if (sum < 0)
		{
			return 0;
		}
		cin >> n;

	}
	return 0;
}

if you have any doubt in this code feel free to ask

#3

can u please write this code using a for loop
]

#4

am not getting whitle(true) condition

#5

this means you have to always take input
there is no restriction on while loop it will always go inside loop, no condition
inside loop we will decide whether we have to further continue or not

#6

can u please wirte this code in the for loop manner it will be very helpful

#7

for loop may be more confusing in this situation
still here is code with for loop

#include<iostream>
using namespace std;

int main() {

	int n;
	int sum = 0;
	cin >> n;
	for(;;)
	{
		sum = sum + n;
		if (sum >= 0)
		{
			cout << n << endl;
		}

		if (sum < 0)
		{
			return 0;
		}
		cin >> n;

	}
	return 0;
}
#8

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