how (s+e)>>1
here>> what is the meaning of this operator
and then what is precision
and why at the end we overshot the value.
Precision and >> how it works there
Hey @TheSourabh where did you saw >> operator ? Moreover I am not able to understand your overshot meaning in context with the doubt. Please elaborate your doubt in simple words 
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how (s+e)>>1 works like always we write (s+e)/2
hello @TheSourabh
this ( >> ) is right shift operator (u will learn it in ur bit manipulation playlist) . it is equivalent to dividing by 2.
(s+e)>>1 = (s+e)/2
how accurate ur answr is precision.
didnt get this.pls explain
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