Can you explain output?
According to me output lines should be opposite
Pointers Arithmetic
Hi @2000bhaveshkumar
First of all we are passing x and y to swap function but there is no change in them when we print them because x and y are not passed by reference so the changes that are made to x and y remains in the swap function only. But here if we add & in the swap function definition like void swap(char *&x, char *&y) then the values of x and y will change.
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